What is the answer to ln(x-2)+ln(x)=1 ?

The answer to ln(x-2)+ln(x)=1 is x=(2+sqrt(4+4e))/2

Solve for x: ln(x-2)+ln(x)=1

The solution is x=(2+sqrt(4+4e))/2

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ln (x - 2) + ln (x) = 1

x = \frac{2 + 4 + 4 e}{2}

Solution steps

ln (x - 2) + ln (x) = 1

Apply log rules

(x - 2) x = e

Solve

(x - 2) x = e : x = \frac{2 + 4 + 4 e}{2}, x = \frac{2 - 4 + 4 e}{2}

x = \frac{2 + 4 + 4 e}{2}, x = \frac{2 - 4 + 4 e}{2}

Verify Solutions:

x = \frac{2 + 4 + 4 e}{2}

True

, x = \frac{2 - 4 + 4 e}{2}

False

The solution is

x = \frac{2 + 4 + 4 e}{2}

lo g_{2} (x) + lo g_{2} (x + 1) = 1

lo g_{x} (125) = - 3

ln (x) + ln (x - 2) = 1

ln (x) + ln (x - 2) = 0

lo g_{\frac{3}{4}} (x) = 2

What is the answer to ln(x-2)+ln(x)=1 ?
The answer to ln(x-2)+ln(x)=1 is x=(2+sqrt(4+4e))/2
Solve for x: ln(x-2)+ln(x)=1
The solution is x=(2+sqrt(4+4e))/2