What is the answer to log_{2}(x^2-x-2)=2 ?

The answer to log_{2}(x^2-x-2)=2 is x=3,x=-2

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log_{2}(x^2-x-2)=2

lo g_{2} (x^{2} - x - 2) = 2

x = 3, x = - 2

Solution steps

lo g_{2} (x^{2} - x - 2) = 2

Apply log rules

x^{2} - x - 2 = 4

Solve

x^{2} - x - 2 = 4 : x = 3, x = - 2

x = 3, x = - 2

lo g_{10} (x) + lo g_{10} (x - 5) = 1

lo g_{2} (3 x - 2) = 4

7 lo g_{5} (x + 27) = 14

1 + lo g_{2} (- 5 x) = 4

ln (x + 1) = 0

What is the answer to log_{2}(x^2-x-2)=2 ?
The answer to log_{2}(x^2-x-2)=2 is x=3,x=-2
Solve for x: log_{2}(x^2-x-2)=2
The solution is x=3,x=-2