What is the answer to log_{3}(x+7)-log_{3}(x-1)=1 ?

The answer to log_{3}(x+7)-log_{3}(x-1)=1 is x=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{3}(x+7)-log_{3}(x-1)=1

lo g_{3} (x + 7) - lo g_{3} (x - 1) = 1

x = 5

Solution steps

lo g_{3} (x + 7) - lo g_{3} (x - 1) = 1

Add

lo g_{3} (x - 1)

to both sides

lo g_{3} (x + 7) - lo g_{3} (x - 1) + lo g_{3} (x - 1) = 1 + lo g_{3} (x - 1)

Simplify

lo g_{3} (x + 7) = 1 + lo g_{3} (x - 1)

Apply log rules

x + 7 = 3 (x - 1)

Solve

x + 7 = 3 (x - 1) : x = 5

x = 5

Verify Solutions:

x = 5

True

The solution is

x = 5

3 lo g_{2} (x) = 2 lo g_{2} (3)

lo g_{10} (2 x - 4) = 2

ln (x) = \frac{3}{2}

lo g_{10} (x^{2} + 64) = 1

4 + lo g_{3} (- 2 x) = 5

What is the answer to log_{3}(x+7)-log_{3}(x-1)=1 ?
The answer to log_{3}(x+7)-log_{3}(x-1)=1 is x=5
Solve for x: log_{3}(x+7)-log_{3}(x-1)=1
The solution is x=5