What is the answer to log_{10}(sqrt(x^2+64))=1 ?

The answer to log_{10}(sqrt(x^2+64))=1 is x=6,x=-6

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log_{10}(sqrt(x^2+64))=1

lo g_{10} (x^{2} + 64) = 1

x = 6, x = - 6

Solution steps

lo g_{10} (x^{2} + 64) = 1

Apply log rules

x^{2} + 64 = 10

Solve

x^{2} + 64 = 10 : x = 6, x = - 6

x = 6, x = - 6

4 + lo g_{3} (- 2 x) = 5

lo g_{2} (x + 2) + lo g_{2} (x - 1) = 2

lo g_{10} (1 + x) = 3

lo g_{2} (x) = 8 + 9 lo g_{x} (2)

ln (3 x - 2) + ln (x - 1) = 2 ln (x)

What is the answer to log_{10}(sqrt(x^2+64))=1 ?
The answer to log_{10}(sqrt(x^2+64))=1 is x=6,x=-6
Solve for x: log_{10}(sqrt(x^2+64))=1
The solution is x=6,x=-6