What is the answer to log_{2}(x)+log_{4}(8x)=6 ?

The answer to log_{2}(x)+log_{4}(8x)=6 is x=8

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log_{2}(x)+log_{4}(8x)=6

lo g_{2} (x) + lo g_{4} (8 x) = 6

x = 8

Solution steps

lo g_{2} (x) + lo g_{4} (8 x) = 6

Apply log rules

x = 8

Verify Solutions:

x = 8

True

The solution is

x = 8

lo g_{4} (3 x - 7) = 1

lo g_{2} (x) + lo g_{4} (x) = 9

lo g_{2} (y^{3}) = 6

lo g_{2} (x + 4) + lo g_{2} (x + 3) = 1

lo g_{a} (2) = \frac{1}{2}

What is the answer to log_{2}(x)+log_{4}(8x)=6 ?
The answer to log_{2}(x)+log_{4}(8x)=6 is x=8
Solve for x: log_{2}(x)+log_{4}(8x)=6
The solution is x=8