What is the answer to log_{4}(x)+log_{4}(x-3)=1 ?

The answer to log_{4}(x)+log_{4}(x-3)=1 is x=4

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log_{4}(x)+log_{4}(x-3)=1

lo g_{4} (x) + lo g_{4} (x - 3) = 1

x = 4

Solution steps

lo g_{4} (x) + lo g_{4} (x - 3) = 1

Apply log rules

x (x - 3) = 4

Solve

x (x - 3) = 4 : x = 4, x = - 1

x = 4, x = - 1

Verify Solutions:

x = 4

True

, x = - 1

False

The solution is

x = 4

lo g_{6} (2 x) - lo g_{6} (x + 1) = 0

ln (x + 1) - ln (x + 3) = 1

ln (x) = ln (x)

y, ln (y) = ln (x) + c

lo g_{2} (x - 5) = 2 - lo g_{2} (x - 2)

What is the answer to log_{4}(x)+log_{4}(x-3)=1 ?
The answer to log_{4}(x)+log_{4}(x-3)=1 is x=4
Solve for x: log_{4}(x)+log_{4}(x-3)=1
The solution is x=4