What is the answer to ln(x+1)-ln(x+3)=1 ?

The answer to ln(x+1)-ln(x+3)=1 is No Solution for x\in\mathbb{R}

Solve for x: ln(x+1)-ln(x+3)=1

The solution is No Solution for x\in\mathbb{R}

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ln (x + 1) - ln (x + 3) = 1

No Solution for x \in R

Solution steps

ln (x + 1) - ln (x + 3) = 1

Add

ln (x + 3)

to both sides

ln (x + 1) - ln (x + 3) + ln (x + 3) = 1 + ln (x + 3)

Simplify

ln (x + 1) = 1 + ln (x + 3)

Apply log rules

x + 1 = e (x + 3)

Solve

x + 1 = e (x + 3) : x = \frac{3 e - 1}{1 - e}

x = \frac{3 e - 1}{1 - e}

Verify Solutions:

x = \frac{3 e - 1}{1 - e}

False

The solution is

No Solution for x \in R

ln (x) = ln (x)

y, ln (y) = ln (x) + c

lo g_{2} (x - 5) = 2 - lo g_{2} (x - 2)

lo g_{3} (x + 2) = 5

lo g_{10} (x) + lo g_{10} (4) = 0

What is the answer to ln(x+1)-ln(x+3)=1 ?
The answer to ln(x+1)-ln(x+3)=1 is No Solution for x\in\mathbb{R}
Solve for x: ln(x+1)-ln(x+3)=1
The solution is No Solution for x\in\mathbb{R}