What is the answer to ln(4-x)=2ln(x)-ln(2) ?

The answer to ln(4-x)=2ln(x)-ln(2) is x=2

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ln(4-x)=2ln(x)-ln(2)

ln (4 - x) = 2 ln (x) - ln (2)

x = 2

Solution steps

ln (4 - x) = 2 ln (x) - ln (2)

Apply log rules

(4 - x) \cdot 2 = x^{2}

Solve

(4 - x) \cdot 2 = x^{2} : x = 2, x = - 4

x = 2, x = - 4

Verify Solutions:

x = 2

True

, x = - 4

False

The solution is

x = 2

lo g_{3} (5 x) = lo g_{3} (160)

ln (7 x + e) = 1

lo g_{3} (x - 2) + lo g_{3} (x - 4) = 2

lo g_{3} (x) + lo g_{3} (2 x - 3) = 3

4 ln (4 b) = ln (2 b)

What is the answer to ln(4-x)=2ln(x)-ln(2) ?
The answer to ln(4-x)=2ln(x)-ln(2) is x=2
Solve for x: ln(4-x)=2ln(x)-ln(2)
The solution is x=2