What is the answer to log_{3}(x)+log_{3}(2x-3)=3 ?

The answer to log_{3}(x)+log_{3}(2x-3)=3 is x= 9/2

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log_{3}(x)+log_{3}(2x-3)=3

lo g_{3} (x) + lo g_{3} (2 x - 3) = 3

x = \frac{9}{2}

Solution steps

lo g_{3} (x) + lo g_{3} (2 x - 3) = 3

Apply log rules

x (2 x - 3) = 27

Solve

x (2 x - 3) = 27 : x = \frac{9}{2}, x = - 3

x = \frac{9}{2}, x = - 3

Verify Solutions:

x = \frac{9}{2}

True

, x = - 3

False

The solution is

x = \frac{9}{2}

4 ln (4 b) = ln (2 b)

ln (x) + ln (x - 6) = 1

2 lo g_{4} (x) - lo g_{4} (x + 5) = 2

x, ln (x) = 2

x, ln (x) = 0

What is the answer to log_{3}(x)+log_{3}(2x-3)=3 ?
The answer to log_{3}(x)+log_{3}(2x-3)=3 is x= 9/2
Solve for x: log_{3}(x)+log_{3}(2x-3)=3
The solution is x= 9/2