What is the answer to ln(2x)=4ln(4x) ?

The answer to ln(2x)=4ln(4x) is x= 1/(e^{\frac{7ln(2)){3}}}

Solve for x: ln(2x)=4ln(4x)

The solution is x= 1/(e^{\frac{7ln(2)){3}}}

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ln (2 x) = 4 ln (4 x)

x = \frac{1}{e ^{\frac{7 l n ( 2 )}{3}}}

Solution steps

ln (2 x) = 4 ln (4 x)

Apply log rules

x = \frac{1}{e ^{\frac{7 l n ( 2 )}{3}}}

Verify Solutions:

x = \frac{1}{e ^{\frac{7 l n ( 2 )}{3}}}

True

The solution is

x = \frac{1}{e ^{\frac{7 l n ( 2 )}{3}}}

ln (- 3 x - 1) - ln (7) = 2

lo g_{5} (x - 3) = 1 - lo g_{5} (x - 7)

2 lo g_{2} (x) - lo g_{2} (2 x) = 3

2 ln (x) = ln (3) + ln (6 - x)

lo g_{2} (x + 5) = 3 - lo g_{2} (x + 7)

What is the answer to ln(2x)=4ln(4x) ?
The answer to ln(2x)=4ln(4x) is x= 1/(e^{\frac{7ln(2)){3}}}
Solve for x: ln(2x)=4ln(4x)
The solution is x= 1/(e^{\frac{7ln(2)){3}}}