What is the answer to ln(-3x-1)-ln(7)=2 ?

The answer to ln(-3x-1)-ln(7)=2 is x=-(7e^2+1)/3

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ln(-3x-1)-ln(7)=2

ln (- 3 x - 1) - ln (7) = 2

x = - \frac{7 e ^{2} + 1}{3}

Solution steps

ln (- 3 x - 1) - ln (7) = 2

Move

ln (7)

to the right side

ln (- 3 x - 1) = 2 + ln (7)

Apply log rules

- 3 x - 1 = 7 e^{2}

Solve

- 3 x - 1 = 7 e^{2} : x = - \frac{7 e ^{2} + 1}{3}

x = - \frac{7 e ^{2} + 1}{3}

Verify Solutions:

x = - \frac{7 e ^{2} + 1}{3}

True

The solution is

x = - \frac{7 e ^{2} + 1}{3}

lo g_{5} (x - 3) = 1 - lo g_{5} (x - 7)

2 lo g_{2} (x) - lo g_{2} (2 x) = 3

2 ln (x) = ln (3) + ln (6 - x)

lo g_{2} (x + 5) = 3 - lo g_{2} (x + 7)

lo g_{2} (x) + lo g_{2} (- 4 x + 12) = 3

What is the answer to ln(-3x-1)-ln(7)=2 ?
The answer to ln(-3x-1)-ln(7)=2 is x=-(7e^2+1)/3
Solve for x: ln(-3x-1)-ln(7)=2
The solution is x=-(7e^2+1)/3