What is the answer to log_{6}(x)+log_{6}(x-9)=2 ?

The answer to log_{6}(x)+log_{6}(x-9)=2 is x=12

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log_{6}(x)+log_{6}(x-9)=2

lo g_{6} (x) + lo g_{6} (x - 9) = 2

x = 12

Solution steps

lo g_{6} (x) + lo g_{6} (x - 9) = 2

Apply log rules

x (x - 9) = 36

Solve

x (x - 9) = 36 : x = 12, x = - 3

x = 12, x = - 3

Verify Solutions:

x = 12

True

, x = - 3

False

The solution is

x = 12

ln (x) = 2.5

e^{l n (x^{2})} + x = 6

lo g_{2} (x + 2) = 2 - lo g_{2} (x + 5)

lo g_{10} (x) - lo g_{10} (6) = 2

lo g_{2} (x + 5) = 2 - lo g_{2} (x + 2)

What is the answer to log_{6}(x)+log_{6}(x-9)=2 ?
The answer to log_{6}(x)+log_{6}(x-9)=2 is x=12
Solve for x: log_{6}(x)+log_{6}(x-9)=2
The solution is x=12