What is the answer to log_{2}(x+2)+log_{2}(x-2)=5 ?

The answer to log_{2}(x+2)+log_{2}(x-2)=5 is x=6

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log_{2}(x+2)+log_{2}(x-2)=5

lo g_{2} (x + 2) + lo g_{2} (x - 2) = 5

x = 6

Solution steps

lo g_{2} (x + 2) + lo g_{2} (x - 2) = 5

Apply log rules

(x + 2) (x - 2) = 32

Solve

(x + 2) (x - 2) = 32 : x = 6, x = - 6

x = 6, x = - 6

Verify Solutions:

x = 6

True

, x = - 6

False

The solution is

x = 6

lo g_{64} (x) = - \frac{1}{3}

lo g_{3} (2 x - 9) = 1

ln (7 - 4 x) = - 10

x, z = ln (x^{2} + y^{2})

lo g_{10} (x^{2} + 3 x) = 1

What is the answer to log_{2}(x+2)+log_{2}(x-2)=5 ?
The answer to log_{2}(x+2)+log_{2}(x-2)=5 is x=6
Solve for x: log_{2}(x+2)+log_{2}(x-2)=5
The solution is x=6