What is the answer to solvefor x,ln(y)=4ln(x) ?

The answer to solvefor x,ln(y)=4ln(x) is x=e^{(ln(y))/4} {y>0}

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solvefor x,ln(y)=4ln(x)

solve for

x, ln (y) = 4 ln (x)

x = e^{\frac{l n ( y )}{4}} {y > 0}

Solution steps

ln (y) = 4 ln (x)

Switch sides

4 ln (x) = ln (y)

Divide both sides by

4

ln (x) = \frac{ln ( y )}{4}

Apply log rules

x = e^{\frac{l n ( y )}{4}}

Verify Solutions:

x = e^{\frac{l n ( y )}{4}} {y > 0}

The solution is

x = e^{\frac{l n ( y )}{4}} {y > 0}

0.25 = lo g_{10} (x)

lo g_{3} (x - 4) + lo g_{3} (x + 4) = 2

lo g_{\frac{1}{2}} (x) = - 2

lo g_{10} (2 x) + lo g_{10} (x) = 11

lo g_{4} (- 2 x + 11) = 2

What is the answer to solvefor x,ln(y)=4ln(x) ?
The answer to solvefor x,ln(y)=4ln(x) is x=e^{(ln(y))/4} {y>0}