What is the answer to 10^{log_{10}(2x)}=x+10 ?

The answer to 10^{log_{10}(2x)}=x+10 is x=10

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10^{log_{10}(2x)}=x+10

1 0^{l o g_{10} (2 x)} = x + 10

x = 10

Solution steps

1 0^{l o g_{10} (2 x)} = x + 10

Apply log rules

2 x = x + 10

Solve

2 x = x + 10 : x = 10

x = 10

Verify Solutions:

x = 10

True

The solution is

x = 10

lo g_{x} (4 x - 3) = 2

0.32 = lo g_{10} (x)

4 lo g_{3} (x - 40) = 16

lo g_{2} (5 x - 8) = 1

lo g_{10} (x) + lo g_{10} (x) = 2

What is the answer to 10^{log_{10}(2x)}=x+10 ?
The answer to 10^{log_{10}(2x)}=x+10 is x=10
Solve for x: 10^{log_{10}(2x)}=x+10
The solution is x=10