What is the answer to 0.32=log_{10}(x) ?

The answer to 0.32=log_{10}(x) is x=10^{0.32}

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0.32=log_{10}(x)

0.32 = lo g_{10} (x)

x = 1 0^{0.32}

Decimal Notation

x = 2.08929 \dots

Solution steps

0.32 = lo g_{10} (x)

Apply log rules

1 0^{0.32} = x

Switch sides

x = 1 0^{0.32}

4 lo g_{3} (x - 40) = 16

lo g_{2} (5 x - 8) = 1

lo g_{10} (x) + lo g_{10} (x) = 2

lo g_{3} (x - 2) + lo g_{3} (2 x - 7) = 2

lo g_{3} ((r + 3)^{2}) = 4

What is the answer to 0.32=log_{10}(x) ?
The answer to 0.32=log_{10}(x) is x=10^{0.32}
Solve for x: 0.32=log_{10}(x)
The solution is x=10^{0.32}