What is the answer to log_{2}((2x^2+7x+5)+9)=3 ?

The answer to log_{2}((2x^2+7x+5)+9)=3 is x=-3/2 ,x=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2}((2x^2+7x+5)+9)=3

lo g_{2} ((2 x^{2} + 7 x + 5) + 9) = 3

x = - \frac{3}{2}, x = - 2

Decimal Notation

x = - 1.5, x = - 2

Solution steps

lo g_{2} ((2 x^{2} + 7 x + 5) + 9) = 3

Apply log rules

2 x^{2} + 7 x + 14 = 8

Solve

2 x^{2} + 7 x + 14 = 8 : x = - \frac{3}{2}, x = - 2

x = - \frac{3}{2}, x = - 2

y = ln (y)

ln (2 x + 1) + ln (x - 3) - 2 ln (x) = 0

lo g_{2} (4 x + 6) = 1

lo g_{6} (x - 2) + lo g_{6} (x + 3) = 2

lo g_{10} (n) = 1000000

What is the answer to log_{2}((2x^2+7x+5)+9)=3 ?
The answer to log_{2}((2x^2+7x+5)+9)=3 is x=-3/2 ,x=-2
Solve for x: log_{2}((2x^2+7x+5)+9)=3
The solution is x=-3/2 ,x=-2