What is the answer to solvefor x,ln(x)+ln(x-1)=0 ?

The answer to solvefor x,ln(x)+ln(x-1)=0 is x=(1+sqrt(5))/2

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solvefor x,ln(x)+ln(x-1)=0

solve for

x, ln (x) + ln (x - 1) = 0

x = \frac{1 + 5}{2}

Decimal Notation

x = 1.61803 \dots

Solution steps

ln (x) + ln (x - 1) = 0

Apply log rules

x (x - 1) = 1

Solve

x (x - 1) = 1 : x = \frac{1 + 5}{2}, x = \frac{1 - 5}{2}

x = \frac{1 + 5}{2}, x = \frac{1 - 5}{2}

Verify Solutions:

x = \frac{1 + 5}{2}

True

, x = \frac{1 - 5}{2}

False

The solution is

x = \frac{1 + 5}{2}

3 ln (2) - ln (4) = - ln (x)

- \frac{ln ( 1 - x )}{x} = 1.5

lo g_{5} (2 x - 3) = 3

lo g_{10} (x + 9) - lo g_{10} (x) = 1

lo g_{4} (x) + lo g_{2} (x) = 6

What is the answer to solvefor x,ln(x)+ln(x-1)=0 ?
The answer to solvefor x,ln(x)+ln(x-1)=0 is x=(1+sqrt(5))/2