What is the answer to log_{10}(x+9)-log_{10}(x)=1 ?

The answer to log_{10}(x+9)-log_{10}(x)=1 is x=1

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log_{10}(x+9)-log_{10}(x)=1

lo g_{10} (x + 9) - lo g_{10} (x) = 1

x = 1

Solution steps

lo g_{10} (x + 9) - lo g_{10} (x) = 1

Add

lo g_{10} (x)

to both sides

lo g_{10} (x + 9) - lo g_{10} (x) + lo g_{10} (x) = 1 + lo g_{10} (x)

Simplify

lo g_{10} (x + 9) = 1 + lo g_{10} (x)

Apply log rules

x + 9 = 10 x

Solve

x + 9 = 10 x : x = 1

x = 1

Verify Solutions:

x = 1

True

The solution is

x = 1

lo g_{4} (x) + lo g_{2} (x) = 6

lo g_{2} (3 x - 4) = 5

lo g_{x} (64) = \frac{3}{2}

0.82 = lo g_{10} (x)

lo g_{3} (- 2 x - 3) = 2

What is the answer to log_{10}(x+9)-log_{10}(x)=1 ?
The answer to log_{10}(x+9)-log_{10}(x)=1 is x=1
Solve for x: log_{10}(x+9)-log_{10}(x)=1
The solution is x=1