What is the answer to 0.678=ln(x^2) ?

The answer to 0.678=ln(x^2) is x=sqrt(e^{0.678)},x=-sqrt(e^{0.678)}

Solve for x: 0.678=ln(x^2)

The solution is x=sqrt(e^{0.678)},x=-sqrt(e^{0.678)}

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0.678 = ln (x^{2})

x = e^{0.678}, x = - e^{0.678}

Decimal Notation

x = 1.40354 \dots, x = - 1.40354 \dots

Solution steps

0.678 = ln (x^{2})

Apply log rules

e^{0.678} = x^{2}

Solve

e^{0.678} = x^{2} : x = e^{0.678}, x = - e^{0.678}

x = e^{0.678}, x = - e^{0.678}

2 lo g_{2} (x + 5) - lo g_{2} (x + 9) = 1

x, ln (y) = 2 ln (x)

ln (x) + ln (x + 1) = ln (12)

lo g_{3} (x) = - \frac{2}{3}

lo g_{5} (x) + 2 = lo g_{5} (7)

What is the answer to 0.678=ln(x^2) ?
The answer to 0.678=ln(x^2) is x=sqrt(e^{0.678)},x=-sqrt(e^{0.678)}
Solve for x: 0.678=ln(x^2)
The solution is x=sqrt(e^{0.678)},x=-sqrt(e^{0.678)}