What is the answer to log_{10}(x+2)-2log_{10}(x)=0 ?

The answer to log_{10}(x+2)-2log_{10}(x)=0 is x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{10}(x+2)-2log_{10}(x)=0

lo g_{10} (x + 2) - 2 lo g_{10} (x) = 0

x = 2

Solution steps

lo g_{10} (x + 2) - 2 lo g_{10} (x) = 0

Apply log rules

x + 2 = x^{2}

Solve

x + 2 = x^{2} : x = 2, x = - 1

x = 2, x = - 1

Verify Solutions:

x = 2

True

, x = - 1

False

The solution is

x = 2

lo g_{10} (x) - lo g_{10} (4) = 2

lo g_{5} (x - 2) + lo g_{5} (x + 2) = 1

lo g_{6} (x + 1) + lo g_{6} (2) = 1

1 + 2 lo g_{4} (t + 1) = 2 lo g_{2} (t)

lo g_{5} (3 x - 2) = 1 + lo g_{5} (x - 4)

What is the answer to log_{10}(x+2)-2log_{10}(x)=0 ?
The answer to log_{10}(x+2)-2log_{10}(x)=0 is x=2
Solve for x: log_{10}(x+2)-2log_{10}(x)=0
The solution is x=2