What is the answer to log_{2}(4)+log_{2}(x+1)=5 ?

The answer to log_{2}(4)+log_{2}(x+1)=5 is x=7

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log_{2}(4)+log_{2}(x+1)=5

lo g_{2} (4) + lo g_{2} (x + 1) = 5

x = 7

Solution steps

lo g_{2} (4) + lo g_{2} (x + 1) = 5

Move

lo g_{2} (4)

to the right side

lo g_{2} (x + 1) = 5 - lo g_{2} (4)

Apply log rules

x + 1 = 8

Solve

x + 1 = 8 : x = 7

x = 7

Verify Solutions:

x = 7

True

The solution is

x = 7

lo g_{x + 8} (2 x^{2} - 16) = 2

lo g_{r (x)} (r (x) (x)^{2 x - 1}) = 2 x - 1

lo g_{w} (3) = \frac{1}{2}

900 = \frac{4000}{ln ( x + 10 )}

ln (4 - x) - ln (x + 1) = ln (2)

What is the answer to log_{2}(4)+log_{2}(x+1)=5 ?
The answer to log_{2}(4)+log_{2}(x+1)=5 is x=7
Solve for x: log_{2}(4)+log_{2}(x+1)=5
The solution is x=7