What is the answer to log_{x+8}(2x^2-16)=2 ?

The answer to log_{x+8}(2x^2-16)=2 is x=-4,x=20

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log_{x+8}(2x^2-16)=2

lo g_{x + 8} (2 x^{2} - 16) = 2

x = - 4, x = 20

Solution steps

lo g_{x + 8} (2 x^{2} - 16) = 2

Apply log rules

\frac{ln ( 2 x ^{2} - 16 )}{ln ( x + 8 )} = 2

Multiply both sides by

ln (x + 8)

\frac{ln ( 2 x ^{2} - 16 )}{ln ( x + 8 )} ln (x + 8) = 2 ln (x + 8)

Simplify

ln (2 x^{2} - 16) = 2 ln (x + 8)

Apply log rules

2 x^{2} - 16 = (x + 8)^{2}

Solve

2 x^{2} - 16 = (x + 8)^{2} : x = - 4, x = 20

x = - 4, x = 20

Verify Solutions:

x = - 4

True

, x = 20

True

The solutions are

x = - 4, x = 20

lo g_{r (x)} (r (x) (x)^{2 x - 1}) = 2 x - 1

lo g_{w} (3) = \frac{1}{2}

900 = \frac{4000}{ln ( x + 10 )}

ln (4 - x) - ln (x + 1) = ln (2)

ln (3 x + 2) + ln (x - 1) = 1

What is the answer to log_{x+8}(2x^2-16)=2 ?
The answer to log_{x+8}(2x^2-16)=2 is x=-4,x=20
Solve for x: log_{x+8}(2x^2-16)=2
The solution is x=-4,x=20