What is the answer to log_{9}(x^2-8x)=1 ?

The answer to log_{9}(x^2-8x)=1 is x=9,x=-1

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log_{9}(x^2-8x)=1

lo g_{9} (x^{2} - 8 x) = 1

x = 9, x = - 1

Solution steps

lo g_{9} (x^{2} - 8 x) = 1

Apply log rules

x^{2} - 8 x = 9

Solve

x^{2} - 8 x = 9 : x = 9, x = - 1

x = 9, x = - 1

lo g_{2} (x + 5) = 2 lo g_{2} (3)

lo g_{x} (2 x) = 2

lo g_{2} (x + 1) + 3 = lo g_{2} (9 x + 4)

lo g_{10} (x) = 1 + lo g_{10} (3)

lo g_{2} (x) + lo g_{4} (x) = 6

What is the answer to log_{9}(x^2-8x)=1 ?
The answer to log_{9}(x^2-8x)=1 is x=9,x=-1
Solve for x: log_{9}(x^2-8x)=1
The solution is x=9,x=-1