What is the answer to log_{2}(x+1)+3=log_{2}(9x+4) ?

The answer to log_{2}(x+1)+3=log_{2}(9x+4) is x=4

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log_{2}(x+1)+3=log_{2}(9x+4)

lo g_{2} (x + 1) + 3 = lo g_{2} (9 x + 4)

x = 4

Solution steps

lo g_{2} (x + 1) + 3 = lo g_{2} (9 x + 4)

Apply log rules

(x + 1) \cdot 8 = 9 x + 4

Solve

(x + 1) \cdot 8 = 9 x + 4 : x = 4

x = 4

Verify Solutions:

x = 4

True

The solution is

x = 4

lo g_{10} (x) = 1 + lo g_{10} (3)

lo g_{2} (x) + lo g_{4} (x) = 6

- 2 = lo g_{10} (2) - lo g_{10} (3 + x)

lo g_{x} (\frac{1}{27}) = - 3

8 x^{2} = 64 x lo g_{2} (x)

What is the answer to log_{2}(x+1)+3=log_{2}(9x+4) ?
The answer to log_{2}(x+1)+3=log_{2}(9x+4) is x=4
Solve for x: log_{2}(x+1)+3=log_{2}(9x+4)
The solution is x=4