What is the answer to log_{2}(x)+log_{4}(x)=6 ?

The answer to log_{2}(x)+log_{4}(x)=6 is x=16

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log_{2}(x)+log_{4}(x)=6

lo g_{2} (x) + lo g_{4} (x) = 6

x = 16

Solution steps

lo g_{2} (x) + lo g_{4} (x) = 6

Apply log rules

x = 16

Verify Solutions:

x = 16

True

The solution is

x = 16

- 2 = lo g_{10} (2) - lo g_{10} (3 + x)

lo g_{x} (\frac{1}{27}) = - 3

8 x^{2} = 64 x lo g_{2} (x)

2 lo g_{3} (x) + lo g_{3} (a) = 0

(ln (x))^{2} - 2 ln (x) - 3 = 0

What is the answer to log_{2}(x)+log_{4}(x)=6 ?
The answer to log_{2}(x)+log_{4}(x)=6 is x=16
Solve for x: log_{2}(x)+log_{4}(x)=6
The solution is x=16