What is the answer to ln(4x)-ln(x+3)=ln(x^2) ?

The answer to ln(4x)-ln(x+3)=ln(x^2) is x=1

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ln(4x)-ln(x+3)=ln(x^2)

ln (4 x) - ln (x + 3) = ln (x^{2})

x = 1

Solution steps

ln (4 x) - ln (x + 3) = ln (x^{2})

Add

ln (x + 3)

to both sides

ln (4 x) - ln (x + 3) + ln (x + 3) = ln (x^{2}) + ln (x + 3)

Simplify

ln (4 x) = ln (x^{2}) + ln (x + 3)

Apply log rules

4 x = x^{2} (x + 3)

Solve

4 x = x^{2} (x + 3) : x = 0, x = 1, x = - 4

x = 0, x = 1, x = - 4

Verify Solutions:

x = 0

False

, x = 1

True

, x = - 4

False

The solution is

x = 1

ln (x + 2) + ln (x - 3) = 0

lo g_{10} (3) = lo g_{10} (x + 1)

lo g_{b} (b^{2}) = 2

x, ln (x - y) = 0

0.61 = lo g_{10} (x)

What is the answer to ln(4x)-ln(x+3)=ln(x^2) ?
The answer to ln(4x)-ln(x+3)=ln(x^2) is x=1
Solve for x: ln(4x)-ln(x+3)=ln(x^2)
The solution is x=1