What is the answer to ln(4x^2)+ln(x)=ln(32) ?

The answer to ln(4x^2)+ln(x)=ln(32) is x=2

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ln(4x^2)+ln(x)=ln(32)

ln (4 x^{2}) + ln (x) = ln (32)

x = 2

Solution steps

ln (4 x^{2}) + ln (x) = ln (32)

Apply log rules

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

3 lo g_{10} (x) - 2 = 10

lo g_{3} (x) = lo g_{9} (x + 12)

0 = ln (3 x + 4)

4.2 = - lo g_{10} (x)

lo g_{2} (2 x) - lo g_{2} (7 x - 15) = 0

What is the answer to ln(4x^2)+ln(x)=ln(32) ?
The answer to ln(4x^2)+ln(x)=ln(32) is x=2
Solve for x: ln(4x^2)+ln(x)=ln(32)
The solution is x=2