What is the answer to 4.2=-log_{10}(x) ?

The answer to 4.2=-log_{10}(x) is x= 1/(10^{4.2)}

Solve for x: 4.2=-log_{10}(x)

The solution is x= 1/(10^{4.2)}

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4.2 = - lo g_{10} (x)

x = \frac{1}{1 0 ^{4.2}}

Decimal Notation

x = 0.00006 \dots

Solution steps

4.2 = - lo g_{10} (x)

Move

lo g_{10} (x)

to the left side

4.2 + lo g_{10} (x) = 0

Move

4.2

to the right side

lo g_{10} (x) = - 4.2

Apply log rules

x = \frac{1}{1 0 ^{4.2}}

Verify Solutions:

x = \frac{1}{1 0 ^{4.2}}

True

The solution is

x = \frac{1}{1 0 ^{4.2}}

lo g_{2} (2 x) - lo g_{2} (7 x - 15) = 0

lo g_{2} (7 x + 6) = 3

lo g_{4} (- x) + lo g_{4} (x + 10) = 2

lo g_{10} (x^{2} - 15 x) = 2

lo g_{2} (\frac{x}{6}) = 8

What is the answer to 4.2=-log_{10}(x) ?
The answer to 4.2=-log_{10}(x) is x= 1/(10^{4.2)}
Solve for x: 4.2=-log_{10}(x)
The solution is x= 1/(10^{4.2)}