What is the answer to log_{3}(x)=log_{9}(x+12) ?

The answer to log_{3}(x)=log_{9}(x+12) is x=4

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log_{3}(x)=log_{9}(x+12)

lo g_{3} (x) = lo g_{9} (x + 12)

x = 4

Solution steps

lo g_{3} (x) = lo g_{9} (x + 12)

Apply log rules

x^{2} = x + 12

Solve

x^{2} = x + 12 : x = 4, x = - 3

x = 4, x = - 3

Verify Solutions:

x = 4

True

, x = - 3

False

The solution is

x = 4

0 = ln (3 x + 4)

4.2 = - lo g_{10} (x)

lo g_{2} (2 x) - lo g_{2} (7 x - 15) = 0

lo g_{2} (7 x + 6) = 3

lo g_{4} (- x) + lo g_{4} (x + 10) = 2

What is the answer to log_{3}(x)=log_{9}(x+12) ?
The answer to log_{3}(x)=log_{9}(x+12) is x=4
Solve for x: log_{3}(x)=log_{9}(x+12)
The solution is x=4