What is the answer to log_{2}(x)=2log_{4}(x+4)-1 ?

The answer to log_{2}(x)=2log_{4}(x+4)-1 is x=4

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log_{2}(x)=2log_{4}(x+4)-1

lo g_{2} (x) = 2 lo g_{4} (x + 4) - 1

x = 4

Solution steps

lo g_{2} (x) = 2 lo g_{4} (x + 4) - 1

Apply log rules

x^{2} \cdot 4 = (x + 4)^{2}

Solve

x^{2} \cdot 4 = (x + 4)^{2} : x = - \frac{4}{3}, x = 4

x = - \frac{4}{3}, x = 4

Verify Solutions:

x = - \frac{4}{3}

False

, x = 4

True

The solution is

x = 4

lo g_{2} (- 6 x - 1) = - 3

0.66 = lo g_{10} (x)

x, ln (y) = 3 + ln (x)

lo g_{2} (2 x - 3) + lo g_{2} (x + 6) = 3

0 = 20 lo g_{10} (w)

What is the answer to log_{2}(x)=2log_{4}(x+4)-1 ?
The answer to log_{2}(x)=2log_{4}(x+4)-1 is x=4
Solve for x: log_{2}(x)=2log_{4}(x+4)-1
The solution is x=4