What is the answer to log_{10}(4)=2-log_{10}(x+5) ?

The answer to log_{10}(4)=2-log_{10}(x+5) is x=20

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log_{10}(4)=2-log_{10}(x+5)

lo g_{10} (4) = 2 - lo g_{10} (x + 5)

x = 20

Solution steps

lo g_{10} (4) = 2 - lo g_{10} (x + 5)

Move

lo g_{10} (x + 5)

to the left side

lo g_{10} (4) + lo g_{10} (x + 5) = 2

Move

lo g_{10} (4)

to the right side

lo g_{10} (x + 5) = 2 - lo g_{10} (4)

Apply log rules

x + 5 = 25

Solve

x + 5 = 25 : x = 20

x = 20

Verify Solutions:

x = 20

True

The solution is

x = 20

0.23 = lo g_{10} (x)

x, 2 ln (x) = ln (y)

lo g_{x + 4} (25 - x^{2}) = 0

ln (1 + e^{- x}) + 2 x = 0

lo g_{6} (7 x) + lo g_{6} (4) = 4

What is the answer to log_{10}(4)=2-log_{10}(x+5) ?
The answer to log_{10}(4)=2-log_{10}(x+5) is x=20
Solve for x: log_{10}(4)=2-log_{10}(x+5)
The solution is x=20