What is the answer to log_{x+4}(25-x^2)=0 ?

The answer to log_{x+4}(25-x^2)=0 is x=2sqrt(6)

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log_{x+4}(25-x^2)=0

lo g_{x + 4} (25 - x^{2}) = 0

x = 26

Decimal Notation

x = 4.89897 \dots

Solution steps

lo g_{x + 4} (25 - x^{2}) = 0

Apply log rules

\frac{ln ( 25 - x ^{2} )}{ln ( x + 4 )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

ln (25 - x^{2}) = 0

Apply log rules

25 - x^{2} = 1

Solve

25 - x^{2} = 1 : x = 26, x = - 26

x = 26, x = - 26

Verify Solutions:

x = 26

True

, x = - 26

False

The solution is

x = 26

ln (1 + e^{- x}) + 2 x = 0

lo g_{6} (7 x) + lo g_{6} (4) = 4

y, ln (y) = - ln (x) + c

lo g_{2} (x + 1) - lo g_{4} (x - 3) = 2

lo g_{x} (3) = - 2

What is the answer to log_{x+4}(25-x^2)=0 ?
The answer to log_{x+4}(25-x^2)=0 is x=2sqrt(6)
Solve for x: log_{x+4}(25-x^2)=0
The solution is x=2sqrt(6)