What is the answer to log_{5}(x^2-7x+7)=0 ?

The answer to log_{5}(x^2-7x+7)=0 is x=6,x=1

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log_{5}(x^2-7x+7)=0

lo g_{5} (x^{2} - 7 x + 7) = 0

x = 6, x = 1

Solution steps

lo g_{5} (x^{2} - 7 x + 7) = 0

Apply log rules

x^{2} - 7 x + 7 = 1

Solve

x^{2} - 7 x + 7 = 1 : x = 6, x = 1

x = 6, x = 1

lo g_{10} (4 x - 3) + lo g_{10} (x) = 0

2 ln (7 x) = 4

lo g_{4} (- x + 7) = lo g_{4} (2 x - 5)

lo g_{2} (x - 12) + lo g_{2} (x) = 6

lo g_{10} (x) = 0.1

What is the answer to log_{5}(x^2-7x+7)=0 ?
The answer to log_{5}(x^2-7x+7)=0 is x=6,x=1
Solve for x: log_{5}(x^2-7x+7)=0
The solution is x=6,x=1