What is the answer to log_{10}(x)=-1/2 ?

The answer to log_{10}(x)=-1/2 is x= 1/(sqrt(10))

Solve for x: log_{10}(x)=-1/2

The solution is x= 1/(sqrt(10))

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lo g_{10} (x) = - \frac{1}{2}

x = \frac{1}{10}

Decimal Notation

x = 0.31622 \dots

Solution steps

lo g_{10} (x) = - \frac{1}{2}

Apply log rules

x = \frac{1}{10}

lo g_{5} (x + 12) - lo g_{5} (x + 3) = 1

11.9 = - lo g_{10} (x)

lo g_{6} (4) + lo g_{6} (x) = 2

x + lo g_{10} (x - 9) = 1

lo g_{6} (x) + lo g_{6} (x + 16) = 2

What is the answer to log_{10}(x)=-1/2 ?
The answer to log_{10}(x)=-1/2 is x= 1/(sqrt(10))
Solve for x: log_{10}(x)=-1/2
The solution is x= 1/(sqrt(10))