What is the answer to solvefor x,log_{x}(y)=1 ?

The answer to solvefor x,log_{x}(y)=1 is x=y {0 1}

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solvefor x,log_{x}(y)=1

solve for

x, lo g_{x} (y) = 1

x = y {0 < y < 1 or y > 1}

Solution steps

lo g_{x} (y) = 1

Apply log rules

\frac{ln ( y )}{ln ( x )} = 1

Multiply both sides by

ln (x)

\frac{ln ( y )}{ln ( x )} ln (x) = 1 \cdot ln (x)

Simplify

ln (y) = ln (x)

Apply log rules

y = x

Switch sides

x = y

Verify Solutions:

x = y {0 < y < 1 or y > 1}

The solution is

x = y {0 < y < 1 or y > 1}

lo g_{2} (8) + lo g_{2} (x + 1) = 4

lo g_{7} (- x) - lo g_{7} (6 - x) = 1

lo g_{3} (3 x - 1) = 2

n lo g_{a} (x) = lo g_{a} (x^{n})

lo g_{2} ((r + 13)^{2}) = 6

What is the answer to solvefor x,log_{x}(y)=1 ?
The answer to solvefor x,log_{x}(y)=1 is x=y {0<y<1\lor y>1}