What is the answer to ln(4)+ln(x+3)=-3 ?

The answer to ln(4)+ln(x+3)=-3 is x= 1/(4e^3)-3

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ln(4)+ln(x+3)=-3

ln (4) + ln (x + 3) = - 3

x = \frac{1}{4 e ^{3}} - 3

Decimal Notation

x = - 2.98755 \dots

Solution steps

ln (4) + ln (x + 3) = - 3

Move

ln (4)

to the right side

ln (x + 3) = - 3 - ln (4)

Apply log rules

x + 3 = \frac{1}{4 e ^{3}}

Solve

x + 3 = \frac{1}{4 e ^{3}} : x = \frac{1}{4 e ^{3}} - 3

x = \frac{1}{4 e ^{3}} - 3

Verify Solutions:

x = \frac{1}{4 e ^{3}} - 3

True

The solution is

x = \frac{1}{4 e ^{3}} - 3

lo g_{2} (x - 2) + lo g_{2} (x + 5) = 1

lo g_{x} (2^{x}) = \frac{x}{4}

ln (a) = ln (3 e^{2}) - 2

lo g_{6} (x - 5) + lo g_{6} (x) = 2

lo g_{6} (x - 1) + lo g_{6} (x) = 1

What is the answer to ln(4)+ln(x+3)=-3 ?
The answer to ln(4)+ln(x+3)=-3 is x= 1/(4e^3)-3
Solve for x: ln(4)+ln(x+3)=-3
The solution is x= 1/(4e^3)-3