What is the answer to log_{2}(3x)-2=log_{2}(2x-5) ?

The answer to log_{2}(3x)-2=log_{2}(2x-5) is x=4

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log_{2}(3x)-2=log_{2}(2x-5)

lo g_{2} (3 x) - 2 = lo g_{2} (2 x - 5)

x = 4

Solution steps

lo g_{2} (3 x) - 2 = lo g_{2} (2 x - 5)

Apply log rules

3 x = (2 x - 5) \cdot 4

Solve

3 x = (2 x - 5) \cdot 4 : x = 4

x = 4

Verify Solutions:

x = 4

True

The solution is

x = 4

26 = \frac{40}{lo g _{10} ( x + 1 )}

x, z = x y + ln (x + y)

ln (d) = a ln (p) + b

lo g_{10} (x) = - 15.4223

lo g_{4} (x + 9) = 2 - lo g_{4} (x - 6)

What is the answer to log_{2}(3x)-2=log_{2}(2x-5) ?
The answer to log_{2}(3x)-2=log_{2}(2x-5) is x=4
Solve for x: log_{2}(3x)-2=log_{2}(2x-5)
The solution is x=4