What is the answer to solvefor x,z=xy+ln(x+y) ?

The answer to solvefor x,z=xy+ln(x+y) is x=(\W(y/(e^{-z-y^2)})-y^2)/y

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solvefor x,z=xy+ln(x+y)

solve for

x, z = x y + ln (x + y)

x = \frac{W ( \frac{y}{e ^{- z - y^{2}}} ) - y ^{2}}{y}

Solution steps

z = x y + ln (x + y)

Switch sides

x y + ln (x + y) = z

Move

x y

to the right side

ln (x + y) = z - x y

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{l n (x + y)} = e^{z - x y}

Simplify

e^{l n (x + y)} : x + y

x + y = e^{z - x y}

Solve

x + y = e^{z - x y} : x = \frac{W ( \frac{y}{e ^{- z - y^{2}}} ) - y ^{2}}{y}

x = \frac{W ( \frac{y}{e ^{- z - y^{2}}} ) - y ^{2}}{y}

ln (d) = a ln (p) + b

lo g_{10} (x) = - 15.4223

lo g_{4} (x + 9) = 2 - lo g_{4} (x - 6)

2 lo g_{2} (x) - lo g_{2} (x + 8) = 2

14 = lo g_{2} (m)

What is the answer to solvefor x,z=xy+ln(x+y) ?
The answer to solvefor x,z=xy+ln(x+y) is x=(\W(y/(e^{-z-y^2)})-y^2)/y