What is the answer to ln((x+5)^{1.2})=9 ?

The answer to ln((x+5)^{1.2})=9 is x=e^{15/2}-5

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ln((x+5)^{1.2})=9

ln ((x + 5)^{1.2}) = 9

x = e^{\frac{15}{2}} - 5

Decimal Notation

x = 1803.04241 \dots

Solution steps

ln ((x + 5)^{1.2}) = 9

Apply log rules

(x + 5)^{1.2} = e^{9}

Solve

(x + 5)^{1.2} = e^{9} : x = e^{\frac{15}{2}} - 5

x = e^{\frac{15}{2}} - 5

lo g_{10} (x + 10) = 10

ln (x) + ln (x - 10) = 2

x, 0 = 2 lo g_{3} (x - 3)

ln (x) + ln (x - 4) = 5

lo g_{2} (x + 7) = 2

What is the answer to ln((x+5)^{1.2})=9 ?
The answer to ln((x+5)^{1.2})=9 is x=e^{15/2}-5
Solve for x: ln((x+5)^{1.2})=9
The solution is x=e^{15/2}-5