What is the answer to ln(x)+ln(x-10)=2 ?

The answer to ln(x)+ln(x-10)=2 is x=(10+sqrt(100+4e^2))/2

Solve for x: ln(x)+ln(x-10)=2

The solution is x=(10+sqrt(100+4e^2))/2

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ln (x) + ln (x - 10) = 2

x = \frac{10 + 100 + 4 e ^{2}}{2}

Decimal Notation

x = 10.69113 \dots

Solution steps

ln (x) + ln (x - 10) = 2

Apply log rules

x (x - 10) = e^{2}

Solve

x (x - 10) = e^{2} : x = \frac{10 + 100 + 4 e ^{2}}{2}, x = \frac{10 - 100 + 4 e ^{2}}{2}

x = \frac{10 + 100 + 4 e ^{2}}{2}, x = \frac{10 - 100 + 4 e ^{2}}{2}

Verify Solutions:

x = \frac{10 + 100 + 4 e ^{2}}{2}

True

, x = \frac{10 - 100 + 4 e ^{2}}{2}

False

The solution is

x = \frac{10 + 100 + 4 e ^{2}}{2}

x, 0 = 2 lo g_{3} (x - 3)

ln (x) + ln (x - 4) = 5

lo g_{2} (x + 7) = 2

lo g_{3} (x - 2) = 2

2 + lo g_{3} (x) = lo g_{9} (x)

What is the answer to ln(x)+ln(x-10)=2 ?
The answer to ln(x)+ln(x-10)=2 is x=(10+sqrt(100+4e^2))/2
Solve for x: ln(x)+ln(x-10)=2
The solution is x=(10+sqrt(100+4e^2))/2