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Popular >

ln(1+x)n=5

Solution

ln (1 + x) n = 5

Solution

x = e^{\frac{5}{n}} - 1 {n < 0 or n > 0}

Solution steps

ln (1 + x) n = 5

Divide both sides by

n

ln (1 + x) = \frac{5}{n}

Apply log rules

1 + x = e^{\frac{5}{n}}

Solve

1 + x = e^{\frac{5}{n}} : x = e^{\frac{5}{n}} - 1

x = e^{\frac{5}{n}} - 1

Verify Solutions:

x = e^{\frac{5}{n}} - 1 {n < 0 or n > 0}

The solution is

x = e^{\frac{5}{n}} - 1 {n < 0 or n > 0}

Popular Examples

ln(8)-ln(k+2)=ln(k)

ln (8) - ln (k + 2) = ln (k)

lo g_{2} (4 X) = 3

log_{9}(30x^2)=7

lo g_{9} (30 x^{2}) = 7

lo g_{x} (81) = 8

log_{10}(6x)=-ln(5x)

lo g_{10} (6 x) = - ln (5 x)

Frequently Asked Questions (FAQ)

What is the answer to ln(1+x)n=5 ?
The answer to ln(1+x)n=5 is x=e^{5/n}-1 {n<0\lor n>0}