What is the answer to log_{10}(5)+log_{10}(4x+1)=0 ?

The answer to log_{10}(5)+log_{10}(4x+1)=0 is x=-1/5

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log_{10}(5)+log_{10}(4x+1)=0

lo g_{10} (5) + lo g_{10} (4 x + 1) = 0

x = - \frac{1}{5}

Decimal

x = - 0.2

Solution steps

lo g_{10} (5) + lo g_{10} (4 x + 1) = 0

Move

lo g_{10} (5)

to the right side

lo g_{10} (4 x + 1) = - lo g_{10} (5)

Apply log rules

4 x + 1 = \frac{1}{5}

Solve

4 x + 1 = \frac{1}{5} : x = - \frac{1}{5}

x = - \frac{1}{5}

Verify Solutions:

x = - \frac{1}{5}

True

The solution is

x = - \frac{1}{5}

ln (7 x) - 6 ln (x^{2}) = ln (2)

lo g_{x} (3125) = - 5

lo g_{4} (192) - lo g_{4} (3 x) = 2

- 17500 = - (8.314) (298) ln (x)

2 ln (x) - 1 = 0

What is the answer to log_{10}(5)+log_{10}(4x+1)=0 ?
The answer to log_{10}(5)+log_{10}(4x+1)=0 is x=-1/5
Solve for x: log_{10}(5)+log_{10}(4x+1)=0
The solution is x=-1/5