What is the answer to log_{2}(x)+1-log_{2}(3)-4=3 ?

The answer to log_{2}(x)+1-log_{2}(3)-4=3 is x=192

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log_{2}(x)+1-log_{2}(3)-4=3

lo g_{2} (x) + 1 - lo g_{2} (3) - 4 = 3

x = 192

Solution steps

lo g_{2} (x) + 1 - lo g_{2} (3) - 4 = 3

Group like terms

lo g_{2} (x) - lo g_{2} (3) + 1 - 4 = 3

Add/Subtract the numbers:

1 - 4 = - 3

lo g_{2} (x) - lo g_{2} (3) - 3 = 3

Move

lo g_{2} (3)

to the right side

lo g_{2} (x) - 3 = 3 + lo g_{2} (3)

Move

3

to the right side

lo g_{2} (x) = lo g_{2} (3) + 6

Apply log rules

x = 192

Verify Solutions:

x = 192

True

The solution is

x = 192

lo g_{3} (x) + lo g_{3} (x) = 2

lo g_{3} (x + 4) = 4 + 2 lo g_{3} (x)

lo g_{2} (x^{2} + 3 x - 6) = 2

- 0.73 = 20 lo g_{10} (\frac{x}{5})

lo g_{3} (x) + lo g_{3} (x - 24) = 4

What is the answer to log_{2}(x)+1-log_{2}(3)-4=3 ?
The answer to log_{2}(x)+1-log_{2}(3)-4=3 is x=192
Solve for x: log_{2}(x)+1-log_{2}(3)-4=3
The solution is x=192