What is the answer to log_{3}(4x-1)-2log_{3}(x)=1 ?

The answer to log_{3}(4x-1)-2log_{3}(x)=1 is x=1,x= 1/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{3}(4x-1)-2log_{3}(x)=1

lo g_{3} (4 x - 1) - 2 lo g_{3} (x) = 1

x = 1, x = \frac{1}{3}

Decimal Notation

x = 1, x = 0.33333 \dots

Solution steps

lo g_{3} (4 x - 1) - 2 lo g_{3} (x) = 1

Apply log rules

4 x - 1 = 3 x^{2}

Solve

4 x - 1 = 3 x^{2} : x = 1, x = \frac{1}{3}

x = 1, x = \frac{1}{3}

Verify Solutions:

x = 1

True

, x = \frac{1}{3}

True

The solutions are

x = 1, x = \frac{1}{3}

lo g_{3} (x + 3) + lo g_{3} (4 x + 7) = 2

y, x = ln (2 y + 1)

ln (x + 9) - ln (x + 7) = 3

lo g_{10} (x + 1) = lo g_{10} (x) + 1

lo g_{3} (\frac{1}{x}) = - 2

What is the answer to log_{3}(4x-1)-2log_{3}(x)=1 ?
The answer to log_{3}(4x-1)-2log_{3}(x)=1 is x=1,x= 1/3
Solve for x: log_{3}(4x-1)-2log_{3}(x)=1
The solution is x=1,x= 1/3