What is the answer to 1.9=-log_{10}(x) ?

The answer to 1.9=-log_{10}(x) is x= 1/(10^{1.9)}

Solve for x: 1.9=-log_{10}(x)

The solution is x= 1/(10^{1.9)}

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1.9 = - lo g_{10} (x)

x = \frac{1}{1 0 ^{1.9}}

Solution steps

1.9 = - lo g_{10} (x)

Move

lo g_{10} (x)

to the left side

1.9 + lo g_{10} (x) = 0

Move

1.9

to the right side

lo g_{10} (x) = - 1.9

Apply log rules

x = \frac{1}{1 0 ^{1.9}}

Verify Solutions:

x = \frac{1}{1 0 ^{1.9}}

True

The solution is

x = \frac{1}{1 0 ^{1.9}}

lo g_{2} (x + 6) + lo g_{2} (x) = 4

lo g_{3} (2 x) = 4

lo g_{3} (2 x - 3) = 4

lo g_{2} (2 x + 6) - lo g_{2} (x) = 3

lo g_{4} (x + 1) = 2 + lo g_{4} (3 x - 2)

What is the answer to 1.9=-log_{10}(x) ?
The answer to 1.9=-log_{10}(x) is x= 1/(10^{1.9)}
Solve for x: 1.9=-log_{10}(x)
The solution is x= 1/(10^{1.9)}