What is the answer to ln(log_{2}(x))=1 ?

The answer to ln(log_{2}(x))=1 is x=2^e

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ln(log_{2}(x))=1

ln (lo g_{2} (x)) = 1

x = 2^{e}

Decimal Notation

x = 6.58088 \dots

Solution steps

ln (lo g_{2} (x)) = 1

Apply log rules

x = 2^{e}

Verify Solutions:

x = 2^{e}

True

The solution is

x = 2^{e}

lo g_{3} (2 x) + lo g_{3} (4) = 5

lo g_{9} (3 - x) = lo g_{3} (x - 1)

lo g_{5} (3) + lo g_{5} (x + 2) = 2

(3 - lo g_{3} (x)) lo g_{3 x} (3) = 1

ln (e^{2 x} + 3) = 2 x + ln (3)

What is the answer to ln(log_{2}(x))=1 ?
The answer to ln(log_{2}(x))=1 is x=2^e
Solve for x: ln(log_{2}(x))=1
The solution is x=2^e