What is the answer to log_{3}(2x)+log_{3}(4)=5 ?

The answer to log_{3}(2x)+log_{3}(4)=5 is x= 243/8

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log_{3}(2x)+log_{3}(4)=5

lo g_{3} (2 x) + lo g_{3} (4) = 5

x = \frac{243}{8}

Solution steps

lo g_{3} (2 x) + lo g_{3} (4) = 5

Move

lo g_{3} (4)

to the right side

lo g_{3} (2 x) = 5 - lo g_{3} (4)

Apply log rules

2 x = \frac{243}{4}

Solve

2 x = \frac{243}{4} : x = \frac{243}{8}

x = \frac{243}{8}

Verify Solutions:

x = \frac{243}{8}

True

The solution is

x = \frac{243}{8}

lo g_{9} (3 - x) = lo g_{3} (x - 1)

lo g_{5} (3) + lo g_{5} (x + 2) = 2

(3 - lo g_{3} (x)) lo g_{3 x} (3) = 1

ln (e^{2 x} + 3) = 2 x + ln (3)

lo g_{3} (2 x + 1) = - 1

What is the answer to log_{3}(2x)+log_{3}(4)=5 ?
The answer to log_{3}(2x)+log_{3}(4)=5 is x= 243/8
Solve for x: log_{3}(2x)+log_{3}(4)=5
The solution is x= 243/8