What is the answer to 3.5=-log_{10}(c) ?

The answer to 3.5=-log_{10}(c) is c= 1/(10^{3.5)}

Solve for c: 3.5=-log_{10}(c)

The solution is c= 1/(10^{3.5)}

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3.5 = - lo g_{10} (c)

c = \frac{1}{1 0 ^{3.5}}

Solution steps

3.5 = - lo g_{10} (c)

Move

lo g_{10} (c)

to the left side

3.5 + lo g_{10} (c) = 0

Move

3.5

to the right side

lo g_{10} (c) = - 3.5

Apply log rules

c = \frac{1}{1 0 ^{3.5}}

Verify Solutions:

c = \frac{1}{1 0 ^{3.5}}

True

The solution is

c = \frac{1}{1 0 ^{3.5}}

N, x = lo g_{a} (N)

lo g_{3} (1 + lo g_{3} (2 x - 7)) = 1

ln (x - 8) = 5

lo g_{5} (x^{2} + 10 x + 1) = 2

lo g_{2} (x - 4) + lo g_{2} (x + 3) = 3

What is the answer to 3.5=-log_{10}(c) ?
The answer to 3.5=-log_{10}(c) is c= 1/(10^{3.5)}
Solve for c: 3.5=-log_{10}(c)
The solution is c= 1/(10^{3.5)}