What is the answer to log_{3}(1+log_{3}(2x-7))=1 ?

The answer to log_{3}(1+log_{3}(2x-7))=1 is x=8

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log_{3}(1+log_{3}(2x-7))=1

lo g_{3} (1 + lo g_{3} (2 x - 7)) = 1

x = 8

Solution steps

lo g_{3} (1 + lo g_{3} (2 x - 7)) = 1

Apply log rules

2 x - 7 = 9

Solve

2 x - 7 = 9 : x = 8

x = 8

Verify Solutions:

x = 8

True

The solution is

x = 8

ln (x - 8) = 5

lo g_{5} (x^{2} + 10 x + 1) = 2

lo g_{2} (x - 4) + lo g_{2} (x + 3) = 3

lo g_{3} (x^{2} - 6 x + 6) = 0

2 ln (x) = lo g_{e^{3}} (216)

What is the answer to log_{3}(1+log_{3}(2x-7))=1 ?
The answer to log_{3}(1+log_{3}(2x-7))=1 is x=8
Solve for x: log_{3}(1+log_{3}(2x-7))=1
The solution is x=8